What is the asymptotes of f(x)=((x-3)(x+2))/((x-4)) ?

The asymptotes of f(x)=((x-3)(x+2))/((x-4)) is Vertical: x=4,Slant: y=x+3

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asymptotes of f(x)=((x-3)(x+2))/((x-4))

asymptotes

f (x) = \frac{( x - 3 ) ( x + 2 )}{( x - 4 )}

Vertical : x = 4, Slant : y = x + 3

Solution steps

Vertical asymptotes of

\frac{( x - 3 ) ( x + 2 )}{x - 4} : x = 4

Horizontal Asymptotes of

\frac{( x - 3 ) ( x + 2 )}{x - 4} :

None

Slant Asymptotes of

\frac{( x - 3 ) ( x + 2 )}{x - 4} : y = x + 3

Vertical : x = 4, Slant : y = x + 3

\frac{6 x}{x ^{2} + 1}

\frac{( x ^{2} )}{( x + 2 ) ^{2}}

f (x) = tan (x^{\frac{1}{x}})

f (x) = \frac{x - 3}{( x ^{2} + 3 )}

f (x) = \frac{( x - 5 )}{( x ^{3} - 9 )}

What is the asymptotes of f(x)=((x-3)(x+2))/((x-4)) ?
The asymptotes of f(x)=((x-3)(x+2))/((x-4)) is Vertical: x=4,Slant: y=x+3