What is the asymptotes of f(x)=((2-x^2))/((x^2-1)) ?

The asymptotes of f(x)=((2-x^2))/((x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=-1

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asymptotes of f(x)=((2-x^2))/((x^2-1))

asymptotes

f (x) = \frac{( 2 - x ^{2} )}{( x ^{2} - 1 )}

Vertical : x = - 1, x = 1, Horizontal : y = - 1

Solution steps

Vertical asymptotes of

\frac{2 - x ^{2}}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{2 - x ^{2}}{x ^{2} - 1} : y = - 1

Slant Asymptotes of

\frac{2 - x ^{2}}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = - 1

f (x) = \frac{x - 8}{2 x - 3}

\frac{4 - 2 x}{5 x - 1}

f (x) = \frac{3 x}{2 x ^{3} - 8 x}

f (x) = \frac{x ^{2} + 6 x + 9}{x - 8}

f (x) = \frac{2 - 3 x}{x}

What is the asymptotes of f(x)=((2-x^2))/((x^2-1)) ?
The asymptotes of f(x)=((2-x^2))/((x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=-1