What is the asymptotes of f(x)=((x^2+x-6))/(2x^2-18) ?

The asymptotes of f(x)=((x^2+x-6))/(2x^2-18) is Vertical: x=3,Horizontal: y= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=((x^2+x-6))/(2x^2-18)

asymptotes

f (x) = \frac{( x ^{2} + x - 6 )}{2 x ^{2} - 18}

Vertical : x = 3, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + x - 6}{2 x ^{2} - 18} : x = 3

Horizontal Asymptotes of

\frac{x ^{2} + x - 6}{2 x ^{2} - 18} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x ^{2} + x - 6}{2 x ^{2} - 18} :

None

Vertical : x = 3, Horizontal : y = \frac{1}{2}

f (x) = y (x - 3)^{2} = x^{2} + 9

y = 3 cot (x)

f (x) = \frac{x ^{2} - 4}{x ^{2} + 2 x}

f (x) = \frac{2}{x ^{2} - 4}

\frac{- x ^{2} + 2 x + 3}{x + 1}

What is the asymptotes of f(x)=((x^2+x-6))/(2x^2-18) ?
The asymptotes of f(x)=((x^2+x-6))/(2x^2-18) is Vertical: x=3,Horizontal: y= 1/2