What is the domain of f(x)=arctan((x-1)/(x+1)) ?

The domain of f(x)=arctan((x-1)/(x+1)) is x -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=arctan((x-1)/(x+1))

domain

f (x) = arctan (\frac{x - 1}{x + 1})

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

X^{2} + 4

x^{2} - 1

(0, - 3), (3, 1)

x^{2} - 6, x \leq 0

y = 1 1^{x}

What is the domain of f(x)=arctan((x-1)/(x+1)) ?
The domain of f(x)=arctan((x-1)/(x+1)) is x<-1\lor x>-1