What is the asymptotes of (x^3-x^2-6x)/(-3x^2-3x+18) ?

The asymptotes of (x^3-x^2-6x)/(-3x^2-3x+18) is Vertical: x=-3,x=2,Slant: y=-1/3 x+2/3

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asymptotes of (x^3-x^2-6x)/(-3x^2-3x+18)

asymptotes

\frac{x ^{3} - x ^{2} - 6 x}{- 3 x ^{2} - 3 x + 18}

Vertical : x = - 3, x = 2, Slant : y = - \frac{1}{3} x + \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{3} - x ^{2} - 6 x}{- 3 x ^{2} - 3 x + 18} : x = - 3, x = 2

Horizontal Asymptotes of

\frac{x ^{3} - x ^{2} - 6 x}{- 3 x ^{2} - 3 x + 18} :

None

Slant Asymptotes of

\frac{x ^{3} - x ^{2} - 6 x}{- 3 x ^{2} - 3 x + 18} : y = - \frac{1}{3} x + \frac{2}{3}

Vertical : x = - 3, x = 2, Slant : y = - \frac{1}{3} x + \frac{2}{3}

\frac{15 x ^{3}}{3 x ^{2} + 1}

f (x) = \frac{x ^{2} - 3}{x + 5}

y = tan (x)

x^{2} \cdot e^{- x}

f (x) = \frac{x \cdot ( x - 1 ) ^{2}}{x - 2}

What is the asymptotes of (x^3-x^2-6x)/(-3x^2-3x+18) ?
The asymptotes of (x^3-x^2-6x)/(-3x^2-3x+18) is Vertical: x=-3,x=2,Slant: y=-1/3 x+2/3