What is the asymptotes of f(x)=(x^2+1)/(x^4-1) ?

The asymptotes of f(x)=(x^2+1)/(x^4-1) is Vertical: x=-1,x=1,Horizontal: y=0

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asymptotes of f(x)=(x^2+1)/(x^4-1)

asymptotes

f (x) = \frac{x ^{2} + 1}{x ^{4} - 1}

Vertical : x = - 1, x = 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x ^{4} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x ^{4} - 1} : y = 0

Slant Asymptotes of

\frac{x ^{2} + 1}{x ^{4} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 0

f (x) = \frac{20 x ^{2}}{5 x ^{2} + 6}

f (x) = \frac{x ^{2} - 1}{x + 4}

\frac{- 2 x + 8}{x ^{2} - 6 x + 8}

f (x) = \frac{x + 2}{- x + 2}

y = 0

What is the asymptotes of f(x)=(x^2+1)/(x^4-1) ?
The asymptotes of f(x)=(x^2+1)/(x^4-1) is Vertical: x=-1,x=1,Horizontal: y=0