What is the asymptotes of f(x)=(x^4)/(3x^2+4x+1) ?

The asymptotes of f(x)=(x^4)/(3x^2+4x+1) is Vertical: x=-1,x=-1/3

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asymptotes of f(x)=(x^4)/(3x^2+4x+1)

asymptotes

f (x) = \frac{x ^{4}}{3 x ^{2} + 4 x + 1}

Vertical : x = - 1, x = - \frac{1}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{4}}{3 x ^{2} + 4 x + 1} : x = - 1, x = - \frac{1}{3}

Horizontal Asymptotes of

\frac{x ^{4}}{3 x ^{2} + 4 x + 1} :

None

Slant Asymptotes of

\frac{x ^{4}}{3 x ^{2} + 4 x + 1} :

None

Vertical : x = - 1, x = - \frac{1}{3}

f (x) = \frac{- 12 x}{3 x ^{3} + x ^{2} + 1}

\frac{5 x + 5}{8 x + 16}

f (x) = \frac{8}{x + 5}

\frac{x - 2}{x ^{3} + 1}

\frac{x ^{3}}{x ^{2} + 2}

What is the asymptotes of f(x)=(x^4)/(3x^2+4x+1) ?
The asymptotes of f(x)=(x^4)/(3x^2+4x+1) is Vertical: x=-1,x=-1/3