What is the asymptotes of f(x)= 1/((x^2-2x-3)) ?

The asymptotes of f(x)= 1/((x^2-2x-3)) is Vertical: x=-1,x=3,Horizontal: y=0

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asymptotes of f(x)= 1/((x^2-2x-3))

asymptotes

f (x) = \frac{1}{( x ^{2} - 2 x - 3 )}

Vertical : x = - 1, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 2 x - 3} : x = - 1, x = 3

Horizontal Asymptotes of

\frac{1}{x ^{2} - 2 x - 3} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} - 2 x - 3} :

None

Vertical : x = - 1, x = 3, Horizontal : y = 0

f (x) = 1 + \frac{7}{x} - \frac{2}{x ^{2}}

f (x) = \frac{( 2 x ^{2} + 2 x - 5 )}{x ^{2} + 2}

f (x) = \frac{( 4 x - 5 )}{2 x ^{2} - 8}

y = \frac{1}{x + 6}

y = \frac{1}{x + 7}

What is the asymptotes of f(x)= 1/((x^2-2x-3)) ?
The asymptotes of f(x)= 1/((x^2-2x-3)) is Vertical: x=-1,x=3,Horizontal: y=0