What is the asymptotes of (t-1)/(sqrt(t^2+8t)-3t) ?

The asymptotes of (t-1)/(sqrt(t^2+8t)-3t) is Vertical: t=0,Horizontal: y=-1/2 ,y=-1/4

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asymptotes of (t-1)/(sqrt(t^2+8t)-3t)

asymptotes

\frac{t - 1}{t ^{2} + 8 t - 3 t}

Vertical : t = 0, Horizontal : y = - \frac{1}{2}, y = - \frac{1}{4}

Solution steps

Vertical asymptotes of

\frac{t - 1}{t ^{2} + 8 t - 3 t} : t = 0

Horizontal Asymptotes of

\frac{t - 1}{t ^{2} + 8 t - 3 t} : y = - \frac{1}{2}, y = - \frac{1}{4}

Slant Asymptotes of

\frac{t - 1}{t ^{2} + 8 t - 3 t} :

None

Vertical : t = 0, Horizontal : y = - \frac{1}{2}, y = - \frac{1}{4}

f (x) = \frac{- 7 x ^{2}}{( x - 5 ) ( x - 4 )}

f (x) = \frac{- 8 x - 7}{2 x - 1}

\frac{x ^{2} - 2 x}{x ^{2} - 1}

f (x) = \frac{7}{x + 5}

\frac{( x ^{2} + 4 x - 21 )}{( x - 3 ) ( x - 4 )}

What is the asymptotes of (t-1)/(sqrt(t^2+8t)-3t) ?
The asymptotes of (t-1)/(sqrt(t^2+8t)-3t) is Vertical: t=0,Horizontal: y=-1/2 ,y=-1/4