What is the asymptotes of f(x)=((x^2))/(2x-8) ?

The asymptotes of f(x)=((x^2))/(2x-8) is Vertical: x=4,Slant: y= 1/2 x+2

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asymptotes of f(x)=((x^2))/(2x-8)

asymptotes

f (x) = \frac{( x ^{2} )}{2 x - 8}

Vertical : x = 4, Slant : y = \frac{1}{2} x + 2

Solution steps

Vertical asymptotes of

\frac{x ^{2}}{2 x - 8} : x = 4

Horizontal Asymptotes of

\frac{x ^{2}}{2 x - 8} :

None

Slant Asymptotes of

\frac{x ^{2}}{2 x - 8} : y = \frac{1}{2} x + 2

Vertical : x = 4, Slant : y = \frac{1}{2} x + 2

f (x) = \frac{4 x ^{2} - 11 x - 3}{x ^{2} + 1}

f (x) = \frac{2 x - 4}{x - 6}

f (x) = \frac{- 2 x ^{2} + x + 3}{x - 1}

\frac{x ^{3}}{( x - 2 ) ^{3}}

f (x) = \frac{2 x - 5}{6 x ^{2} - 7 x - 3}

What is the asymptotes of f(x)=((x^2))/(2x-8) ?
The asymptotes of f(x)=((x^2))/(2x-8) is Vertical: x=4,Slant: y= 1/2 x+2