What is the asymptotes of (8x^2+1)/(2x^2+7x-4) ?

The asymptotes of (8x^2+1)/(2x^2+7x-4) is Vertical: x=-4,x= 1/2 ,Horizontal: y=4

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asymptotes of (8x^2+1)/(2x^2+7x-4)

asymptotes

\frac{8 x ^{2} + 1}{2 x ^{2} + 7 x - 4}

Vertical : x = - 4, x = \frac{1}{2}, Horizontal : y = 4

Solution steps

Vertical asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 7 x - 4} : x = - 4, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 7 x - 4} : y = 4

Slant Asymptotes of

\frac{8 x ^{2} + 1}{2 x ^{2} + 7 x - 4} :

None

Vertical : x = - 4, x = \frac{1}{2}, Horizontal : y = 4

f (x) = \frac{3 x ^{3} - 2 x}{x ^{2} + 2}

g (x) = 3 cos (4 x)

f (x) = \frac{x ^{4}}{( x ^{2} + 3 )}

f (x) = \frac{x + 5}{2 x - 2}

f (x) = lo g_{3} (x - 6)

What is the asymptotes of (8x^2+1)/(2x^2+7x-4) ?
The asymptotes of (8x^2+1)/(2x^2+7x-4) is Vertical: x=-4,x= 1/2 ,Horizontal: y=4