What is the asymptotes of f(x)=(x^2+4x)/(x^2-x-6) ?

The asymptotes of f(x)=(x^2+4x)/(x^2-x-6) is Vertical: x=-2,x=3,Horizontal: y=1

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asymptotes of f(x)=(x^2+4x)/(x^2-x-6)

asymptotes

f (x) = \frac{x ^{2} + 4 x}{x ^{2} - x - 6}

Vertical : x = - 2, x = 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 4 x}{x ^{2} - x - 6} : x = - 2, x = 3

Horizontal Asymptotes of

\frac{x ^{2} + 4 x}{x ^{2} - x - 6} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 4 x}{x ^{2} - x - 6} :

None

Vertical : x = - 2, x = 3, Horizontal : y = 1

f (x) = \frac{- 4 x ^{2} - 2 x}{- 2 x - 2}

f (x) = \frac{2 x - 1}{- x - 2}

\frac{( 2 x + 1 ) ( x - 2 ) ^{2}}{x ( x + 1 ) ^{2}}

f (x) = \frac{( x - 2 )}{( x ^{2} - 4 x + 5 )}

f (x) = 1 + \frac{7}{x} - \frac{8}{x ^{2}}

What is the asymptotes of f(x)=(x^2+4x)/(x^2-x-6) ?
The asymptotes of f(x)=(x^2+4x)/(x^2-x-6) is Vertical: x=-2,x=3,Horizontal: y=1