What is the asymptotes of f(x)= 1/((x+3)(x-4)) ?

The asymptotes of f(x)= 1/((x+3)(x-4)) is Vertical: x=-3,x=4,Horizontal: y=0

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asymptotes of f(x)= 1/((x+3)(x-4))

asymptotes

f (x) = \frac{1}{( x + 3 ) ( x - 4 )}

Vertical : x = - 3, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{( x + 3 ) ( x - 4 )} : x = - 3, x = 4

Horizontal Asymptotes of

\frac{1}{( x + 3 ) ( x - 4 )} : y = 0

Slant Asymptotes of

\frac{1}{( x + 3 ) ( x - 4 )} :

None

Vertical : x = - 3, x = 4, Horizontal : y = 0

f (x) = lo g_{6} (x - 3) + 7

f (x) = 3 lo g_{2} (x)

\frac{6 x}{x ^{2} - 9}

ln (x - 2)

f (x) = 5 + 2^{3 x - 1}

What is the asymptotes of f(x)= 1/((x+3)(x-4)) ?
The asymptotes of f(x)= 1/((x+3)(x-4)) is Vertical: x=-3,x=4,Horizontal: y=0