What is the asymptotes of f(x)=(-2x^2+5-1)/(2x-1) ?

The asymptotes of f(x)=(-2x^2+5-1)/(2x-1) is Vertical: x= 1/2 ,Slant: y=-x-1/2

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asymptotes of f(x)=(-2x^2+5-1)/(2x-1)

asymptotes

f (x) = \frac{- 2 x ^{2} + 5 - 1}{2 x - 1}

Vertical : x = \frac{1}{2}, Slant : y = - x - \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{- 2 x ^{2} + 5 - 1}{2 x - 1} : x = \frac{1}{2}

Horizontal Asymptotes of

\frac{- 2 x ^{2} + 5 - 1}{2 x - 1} :

None

Slant Asymptotes of

\frac{- 2 x ^{2} + 5 - 1}{2 x - 1} : y = - x - \frac{1}{2}

Vertical : x = \frac{1}{2}, Slant : y = - x - \frac{1}{2}

f (x) = 2 x - 4 x^{2} - x + 1

f (x) = \frac{x + 4}{2 x - 8}

\frac{8 x ^{2}}{7 x ^{3} - x ^{2}}

\frac{x ^{2} - 2 x - 15}{x + 3}

f (x) = x^{2} - x - 6

What is the asymptotes of f(x)=(-2x^2+5-1)/(2x-1) ?
The asymptotes of f(x)=(-2x^2+5-1)/(2x-1) is Vertical: x= 1/2 ,Slant: y=-x-1/2