What is the asymptotes of f(x)=((x-4))/(2x^2-1) ?

The asymptotes of f(x)=((x-4))/(2x^2-1) is Vertical: x=-1/(sqrt(2)),x= 1/(sqrt(2)),Horizontal: y=0

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asymptotes of f(x)=((x-4))/(2x^2-1)

asymptotes

f (x) = \frac{( x - 4 )}{2 x ^{2} - 1}

Vertical : x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x - 4}{2 x ^{2} - 1} : x = - \frac{1}{2}, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{x - 4}{2 x ^{2} - 1} : y = 0

Slant Asymptotes of

\frac{x - 4}{2 x ^{2} - 1} :

None

Vertical : x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal : y = 0

f (x) = \frac{x ^{2} - 4}{x ^{3} + 2 x ^{2}}

f (x) = \frac{5 x + 15}{3 x ^{2} + 10 x + 3}

f (x) = \frac{3 e ^{x}}{e ^{x} - 1}

\frac{- 6 x + 11}{2 x + 7}

f (x) = \frac{x + 1}{x ^{2} + 5 x + 4}

What is the asymptotes of f(x)=((x-4))/(2x^2-1) ?
The asymptotes of f(x)=((x-4))/(2x^2-1) is Vertical: x=-1/(sqrt(2)),x= 1/(sqrt(2)),Horizontal: y=0