What is the extreme f(x)=2x^3-2x^2-2x+3 ?

The extreme f(x)=2x^3-2x^2-2x+3 is Maximum(-1/3 , 91/27),Minimum(1,1)

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extreme f(x)=2x^3-2x^2-2x+3

extreme points

f (x) = 2 x^{3} - 2 x^{2} - 2 x + 3

Maximum (- \frac{1}{3}, \frac{91}{27}), Minimum (1, 1)

Solution steps

f^{'} (x) = 6 x^{2} - 4 x - 2

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

2 x^{3} - 2 x^{2} - 2 x + 3 : \frac{91}{27}

Maximum (- \frac{1}{3}, \frac{91}{27})

Plug

x = 1

into

2 x^{3} - 2 x^{2} - 2 x + 3 : 1

Minimum (1, 1)

Maximum (- \frac{1}{3}, \frac{91}{27}), Minimum (1, 1)

f (x) = x^{2} - 12 x + 5

x + 1 + \frac{1}{x ^{2} + 1}

4 x - 3 y = - 18

f (x) = 3 (x^{\frac{1}{2}} - 3)

x - 12

What is the extreme f(x)=2x^3-2x^2-2x+3 ?
The extreme f(x)=2x^3-2x^2-2x+3 is Maximum(-1/3 , 91/27),Minimum(1,1)