extreme f(x)=2x^3-2x^2-2x+3

Solução

puntos extremos

f (x) = 2 x^{3} - 2 x^{2} - 2 x + 3

M \overset{a}{ˊ} ximo (- \frac{1}{3}, \frac{91}{27}), M \overset{ı}{ˊ} nimo (1, 1)

Passos da solução

f^{'} (x) = 6 x^{2} - 4 x - 2

Find intervals:

Crescente

: - \infty < x < - \frac{1}{3},

Decrescente

: - \frac{1}{3} < x < 1,

Crescente

: 1 < x < \infty

Inserir

x = - \frac{1}{3}

2 x^{3} - 2 x^{2} - 2 x + 3 : \frac{91}{27}

M \overset{a}{ˊ} ximo (- \frac{1}{3}, \frac{91}{27})

Inserir

x = 1

2 x^{3} - 2 x^{2} - 2 x + 3 : 1

M \overset{ı}{ˊ} nimo (1, 1)

M \overset{a}{ˊ} ximo (- \frac{1}{3}, \frac{91}{27}), M \overset{ı}{ˊ} nimo (1, 1)

f (x) = x^{2} - 12 x + 5

x + 1 + \frac{1}{x ^{2} + 1}

4 x - 3 y = - 18

f (x) = 3 (x^{\frac{1}{2}} - 3)

x - 12