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Popular >

inflection sqrt(2x^2+3x+1)

Solution

inflection points

2 x^{2} + 3 x + 1

Solution

None

Solution steps

f^{''} (x) = - \frac{1}{4 ( 2 x ^{2} + 3 x + 1 ) 2 x ^{2} + 3 x + 1}

Find intervals:

Concave Downward

: - \infty < x < - 1,

Concave Downward

: - \frac{1}{2} < x < \infty

None

Popular Examples

domain of (2x-3)/(x^2-1)domain

\frac{2 x - 3}{x ^{2} - 1}

inverse of f(x)=-2x-9 inverse

f (x) = - 2 x - 9

inverse of 27a^6 inverse

27 a^{6}

domain of f(x)=(-4.8)(4.8)domain

f (x) = (- 4.8) (4.8)

inverse of-4x-12 inverse

- 4 x - 12

Frequently Asked Questions (FAQ)

What is the inflection sqrt(2x^2+3x+1) ?
The inflection sqrt(2x^2+3x+1) is None