What is the p(x)=x^5-4x^4+x^3-x^2-2x+2015 ?

The p(x)=x^5-4x^4+x^3-x^2-2x+2015 is

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p(x)=x^5-4x^4+x^3-x^2-2x+2015

p (x) = x^{5} - 4 x^{4} + x^{3} - x^{2} - 2 x + 2015

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

X Intercepts : (- 3.95457 \dots, 0), Y Intercepts : (0, 2015)

Asymptotes : None

Extreme Points : Maximum (- 0.36530 \dots, 2015.47067 \dots), Minimum (3.06061 \dots, 1945.75260 \dots)

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

x^{5} - 4 x^{4} + x^{3} - x^{2} - 2 x + 2015 : - \infty < x < \infty

Range of

x^{5} - 4 x^{4} + x^{3} - x^{2} - 2 x + 2015 : - \infty < f (x) < \infty

Axis interception points of

x^{5} - 4 x^{4} + x^{3} - x^{2} - 2 x + 2015 :

X Intercepts

: (- 3.95457 \dots, 0),

Y Intercepts

: (0, 2015)

Asymptotes of

x^{5} - 4 x^{4} + x^{3} - x^{2} - 2 x + 2015 :

None

Extreme Points of

x^{5} - 4 x^{4} + x^{3} - x^{2} - 2 x + 2015 :

Maximum

(- 0.36530 \dots, 2015.47067 \dots),

Minimum

(3.06061 \dots, 1945.75260 \dots)

y = \frac{( x ^{2} - 3 x + 1 )}{( x - 3 )}

y = ln (\frac{( 3 - x )}{x})

p (x) = - x^{4} + 2 x^{3} - 4 x + 6

f (x) = (x - 2)^{4} \cdot (x + 1)^{3}

y = (1 + p) x + p^{2}

What is the p(x)=x^5-4x^4+x^3-x^2-2x+2015 ?
The p(x)=x^5-4x^4+x^3-x^2-2x+2015 is