What is the extreme f(x)=2x^3-6x^2+5 ?

The extreme f(x)=2x^3-6x^2+5 is Maximum(0,5),Minimum(2,-3)

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extreme f(x)=2x^3-6x^2+5

extreme points

f (x) = 2 x^{3} - 6 x^{2} + 5

Maximum (0, 5), Minimum (2, - 3)

Solution steps

f^{'} (x) = 6 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

2 x^{3} - 6 x^{2} + 5 : 5

Maximum (0, 5)

Plug

x = 2

into

2 x^{3} - 6 x^{2} + 5 : - 3

Minimum (2, - 3)

Maximum (0, 5), Minimum (2, - 3)

tan (x) d x

f (x) = \frac{x ^{2} - 2 x - 1}{2 x - 8}

f (x) = \frac{8 x}{5 x - 6}

f (x) = x + 4

f (x) = x + sin (x)

What is the extreme f(x)=2x^3-6x^2+5 ?
The extreme f(x)=2x^3-6x^2+5 is Maximum(0,5),Minimum(2,-3)