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Popular >

f(1)=|2x+2|+log_{2}(x^2+1)

Solution

f (1) = ∣ 2 x + 2 ∣ + lo g_{2} (x^{2} + 1)

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 1

Y Intercepts : (0, 2)

Asymptotes : None

Extreme Points : Minimum (- 1, 1)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [1, \infty)

Solution steps

Domain of

∣ 2 x + 2 ∣ + lo g_{2} (x^{2} + 1) : - \infty < x < \infty

Range of

∣ 2 x + 2 ∣ + lo g_{2} (x^{2} + 1) : f (x) \geq 1

Axis interception points of

∣ 2 x + 2 ∣ + lo g_{2} (x^{2} + 1) :

Y Intercepts

: (0, 2)

Asymptotes of

∣ 2 x + 2 ∣ + lo g_{2} (x^{2} + 1) :

None

Extreme Points of

∣ 2 x + 2 ∣ + lo g_{2} (x^{2} + 1) :

Minimum

(- 1, 1)

Popular Examples

f (x) = 9 x^{2} - 8 x - 1

f (- 10) = 15 x + 2

f(x)=((5x+3))/x

f (x) = \frac{( 5 x + 3 )}{x}

y = 3 x - 2

f(a)=2a^2+19a-25

f (a) = 2 a^{2} + 19 a - 25

Frequently Asked Questions (FAQ)

What is the f(1)=|2x+2|+log_{2}(x^2+1) ?
The f(1)=|2x+2|+log_{2}(x^2+1) is