What is the inverse of f(x)=-2x^2+5 ?

The inverse of f(x)=-2x^2+5 is sqrt(-(x-5)/2),-sqrt(-(x-5)/2)

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inverse of f(x)=-2x^2+5

inverse

f (x) = - 2 x^{2} + 5

- \frac{x - 5}{2}, - - \frac{x - 5}{2}

Solution steps

y = - 2 x^{2} + 5

Replace

x

with

y

x = - 2 y^{2} + 5

Solve for

y, x = - 2 y^{2} + 5

- \frac{x - 5}{2}, - - \frac{x - 5}{2}

4 + 3 y = - 12

f (x) = t + 14

f (x) = 2 x^{2} - 2 x + 1

(- 4, - 2), (- 8, 3)

What is the inverse of f(x)=-2x^2+5 ?
The inverse of f(x)=-2x^2+5 is sqrt(-(x-5)/2),-sqrt(-(x-5)/2)