en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(t)=5t^2-18t-120

Solution

f (t) = 5 t^{2} - 18 t - 120

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq - \frac{681}{5}

X Intercepts : (\frac{9 + 681}{5}, 0), (\frac{9 - 681}{5}, 0), Y Intercepts : (0, - 120)

Vertex : Minimum (\frac{9}{5}, - \frac{681}{5})

Inverse : \frac{9 + 5 t + 681}{5}, \frac{9 - 5 t + 681}{5}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{681}{5}, \infty)

Solution steps

Domain of

5 t^{2} - 18 t - 120 : - \infty < t < \infty

Range of

5 t^{2} - 18 t - 120 : f (t) \geq - \frac{681}{5}

Axis interception points of

5 t^{2} - 18 t - 120 :

X Intercepts

: (\frac{9 + 681}{5}, 0), (\frac{9 - 681}{5}, 0),

Y Intercepts

: (0, - 120)

Vertex of

5 t^{2} - 18 t - 120 :

Minimum

(\frac{9}{5}, - \frac{681}{5})

Inverse of

5 t^{2} - 18 t - 120 : \frac{9 + 5 t + 681}{5}, \frac{9 - 5 t + 681}{5}

Popular Examples

f(x)=((e^{2x}-1))/((e^{2x)+1)}

f (x) = \frac{( e ^{2 x} - 1 )}{( e ^{2 x} + 1 )}

f(x)=e^{cos(3x)}

f (x) = e^{c o s (3 x)}

f(x)=((x^2-1))/(((x+1)^2))

f (x) = \frac{( x ^{2} - 1 )}{( ( x + 1 ) ^{2} )}

f(x)=8x^6+19x^3+27

f (x) = 8 x^{6} + 19 x^{3} + 27

f(t)=((log_{10}(t)))/((1+t))

f (t) = \frac{( lo g _{10} ( t ) )}{( 1 + t )}

Frequently Asked Questions (FAQ)

What is the f(t)=5t^2-18t-120 ?
The f(t)=5t^2-18t-120 is