What is the f(s)=((s^2+2))/((s^3-2s^2-s+2)) ?

The f(s)=((s^2+2))/((s^3-2s^2-s+2)) is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(s)=((s^2+2))/((s^3-2s^2-s+2))

f (s) = \frac{( s ^{2} + 2 )}{( s ^{3} - 2 s ^{2} - s + 2 )}

Domain : s < - 1 or - 1 < s < 1 or 1 < s < 2 or s > 2

Range : f (s) < 0 or f (s) > 0

Y Intercepts : (0, 1)

Asymptotes : Vertical s = - 1, s = 1, s = 2, Horizontal y = 0

Extreme Points : Minimum (- 0.15297 \dots, 0.96233 \dots), Maximum (1.46263 \dots, - 6.76112 \dots)

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 1) \cup (1, 2) \cup (2, \infty)

Range : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{s ^{2} + 2}{s ^{3} - 2 s ^{2} - s + 2} : s < - 1 or - 1 < s < 1 or 1 < s < 2 or s > 2

Range of

\frac{s ^{2} + 2}{s ^{3} - 2 s ^{2} - s + 2} : f (s) < 0 or f (s) > 0

Axis interception points of

\frac{s ^{2} + 2}{s ^{3} - 2 s ^{2} - s + 2} :

Y Intercepts

: (0, 1)

Asymptotes of

\frac{s ^{2} + 2}{s ^{3} - 2 s ^{2} - s + 2} :

Vertical

: s = - 1, s = 1, s = 2,

Horizontal

: y = 0

Extreme Points of

\frac{s ^{2} + 2}{s ^{3} - 2 s ^{2} - s + 2} :

Minimum

(- 0.15297 \dots, 0.96233 \dots),

Maximum

(1.46263 \dots, - 6.76112 \dots)

y = \frac{3}{8 \cdot x + 2}

f (x) = (3 x - 6)^{\frac{1}{3}} + 5

f (x) = e^{x^{2}} \cdot lo g_{10} (2 x)

f (x) = 4 x^{3} + 4 x^{2} - 21 x - 9

y = 5 cos^{- 4} (x)

What is the f(s)=((s^2+2))/((s^3-2s^2-s+2)) ?
The f(s)=((s^2+2))/((s^3-2s^2-s+2)) is