What is p(x)=3,x^2-x^2+3x-7=(x+2) ?

The solution to p(x)=3,x^2-x^2+3x-7=(x+2) is

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p(x)=3,x^2-x^2+3x-7=(x+2)

p (x) = 3, x^{2} - x^{2} + 3 x - 7 = (x + 2)

(x = \frac{9}{2}, p = 3)

Solution steps

[p = 3 x^{2} - x^{2} + 3 x - 7 = (x + 2)]

Solve

x^{2} - x^{2} + 3 x - 7 = (x + 2) : x = \frac{9}{2}

Plug the solutions

x = \frac{9}{2}

into

p = 3

For

p = 3

, subsitute

x

with

\frac{9}{2} : p = 3

Verify solutions by plugging them into the original equations

Therefore, the final solution for

p = 3, x^{2} - x^{2} + 3 x - 7 = (x + 2)

(x = \frac{9}{2}, p = 3)

f (x) = \frac{2}{( x - 3 )}

f (x) = (\frac{3 x}{( x ^{2} + 1 )})^{4}

y = (x + 3) 2 - 4

f (m) = \frac{32}{3 \cdot m}

f (x) = - 4 cos^{2} (x)

What is p(x)=3,x^2-x^2+3x-7=(x+2) ?
The solution to p(x)=3,x^2-x^2+3x-7=(x+2) is