What is the y= 2/(((3x+1)^2))+4/(((4x-3)^2)) ?

The y= 2/(((3x+1)^2))+4/(((4x-3)^2)) is

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y= 2/(((3x+1)^2))+4/(((4x-3)^2))

y = \frac{2}{( ( 3 x + 1 ) ^{2} )} + \frac{4}{( ( 4 x - 3 ) ^{2} )}

Domain : x < - \frac{1}{3} or - \frac{1}{3} < x < \frac{3}{4} or x > \frac{3}{4}

Y Intercepts : (0, \frac{22}{9})

Asymptotes : Vertical x = - \frac{1}{3}, x = \frac{3}{4}, Horizontal y = 0

Extreme Points : Minimum (0.19770 \dots, 1.60760 \dots)

Interval Notation

Domain : (- \infty, - \frac{1}{3}) \cup (- \frac{1}{3}, \frac{3}{4}) \cup (\frac{3}{4}, \infty)

Solution steps

Domain of

\frac{2}{( 3 x + 1 ) ^{2}} + \frac{4}{( 4 x - 3 ) ^{2}} : x < - \frac{1}{3} or - \frac{1}{3} < x < \frac{3}{4} or x > \frac{3}{4}

Axis interception points of

\frac{2}{( 3 x + 1 ) ^{2}} + \frac{4}{( 4 x - 3 ) ^{2}} :

Y Intercepts

: (0, \frac{22}{9})

Asymptotes of

\frac{2}{( 3 x + 1 ) ^{2}} + \frac{4}{( 4 x - 3 ) ^{2}} :

Vertical

: x = - \frac{1}{3}, x = \frac{3}{4},

Horizontal

: y = 0

Extreme Points of

\frac{2}{( 3 x + 1 ) ^{2}} + \frac{4}{( 4 x - 3 ) ^{2}} :

Minimum

(0.19770 \dots, 1.60760 \dots)

f (t) = \frac{cos ^{3} ( t )}{t}

y = (e^{x} + e^{- x})^{2}

y = 7 x^{2} + 2 x + 3

f (x) = \frac{( x - 7 )}{( x + 12 )}

p (x) = x^{2} + 3 x + 2

What is the y= 2/(((3x+1)^2))+4/(((4x-3)^2)) ?
The y= 2/(((3x+1)^2))+4/(((4x-3)^2)) is