What is the range of f(x)=-1/(sqrt(x)) ?

The range of f(x)=-1/(sqrt(x)) is f(x)<0

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range of f(x)=-1/(sqrt(x))

range

f (x) = - \frac{1}{x}

f (x) < 0

Interval Notation

(- \infty, 0)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

- \frac{1}{x} : x > 0

Extreme Points of

- \frac{1}{x} :

None

Find the range for the interval

0 < x < \infty : - \infty < f (x) < 0

Combine the ranges of all domain intervals to obtain the function range

f (x) < 0

49 x + 64

y = (\frac{x}{a ^{2} - x ^{2}} - arcsin (\frac{x}{a}))

f (x) = (\frac{1}{5})^{x}

f (x) = x^{2} - 4 x + 10

f (x) = \frac{1}{1 - x}

What is the range of f(x)=-1/(sqrt(x)) ?
The range of f(x)=-1/(sqrt(x)) is f(x)<0