What is the domain of g(x)=sqrt(x^2-2x-8) ?

The domain of g(x)=sqrt(x^2-2x-8) is x = 4

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domain of g(x)=sqrt(x^2-2x-8)

domain

g (x) = x^{2} - 2 x - 8

x \leq - 2 or x \geq 4

Interval Notation

(- \infty, - 2] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 4

The function domain

x \leq - 2 or x \geq 4

f (x) = - \frac{21}{( 5 + x ) ^{2}}

f (x) = 25 - x^{2} - x + 1

2 tan (\frac{π x}{2})

Y (x) - 5 = \frac{- 1}{2 ( \frac{x - 1}{2} )}

y = 2 x + 1

What is the domain of g(x)=sqrt(x^2-2x-8) ?
The domain of g(x)=sqrt(x^2-2x-8) is x<=-2\lor x>= 4