What is the y=((50t^2+300t+1500))/((t^2+30)) ?

The y=((50t^2+300t+1500))/((t^2+30)) is

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y=((50t^2+300t+1500))/((t^2+30))

y = \frac{( 50 t ^{2} + 300 t + 1500 )}{( t ^{2} + 30 )}

Domain : - \infty < t < \infty

Range : - 530 + 50 \leq f (t) \leq 530 + 50

Y Intercepts : (0, 50)

Asymptotes : Horizontal y = 50

Extreme Points : Minimum (- 30, 5 (10 - 30)), Maximum (30, 5 (10 + 30))

Interval Notation

Domain : (- \infty, \infty)

Range : [- 530 + 50, 530 + 50]

Solution steps

Domain of

\frac{50 t ^{2} + 300 t + 1500}{t ^{2} + 30} : - \infty < t < \infty

Range of

\frac{50 t ^{2} + 300 t + 1500}{t ^{2} + 30} : - 530 + 50 \leq f (t) \leq 530 + 50

Axis interception points of

\frac{50 t ^{2} + 300 t + 1500}{t ^{2} + 30} :

Y Intercepts

: (0, 50)

Asymptotes of

\frac{50 t ^{2} + 300 t + 1500}{t ^{2} + 30} :

Horizontal

: y = 50

Extreme Points of

\frac{50 t ^{2} + 300 t + 1500}{t ^{2} + 30} :

Minimum

(- 30, 5 (10 - 30)),

Maximum

(30, 5 (10 + 30))

f (y) = 6 y^{2} + 7 y - 48

f (x) = \frac{1}{6 \cdot ln ( ( x ^{2} - 2 2 x ^{2} - 2 ) ^{4} )}

f (n) = \frac{( 9 n ^{6} - 11 )}{8}

f (p) = 9 p^{2} - 15 p - 13

f (x) = \frac{x}{7 + 10}

What is the y=((50t^2+300t+1500))/((t^2+30)) ?
The y=((50t^2+300t+1500))/((t^2+30)) is