What is the p(x)=(x^2-x+1)(x^2+x+1)+2x^2-29 ?

The p(x)=(x^2-x+1)(x^2+x+1)+2x^2-29 is

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p(x)=(x^2-x+1)(x^2+x+1)+2x^2-29

p (x) = (x^{2} - x + 1) (x^{2} + x + 1) + 2 x^{2} - 29

Domain : - \infty < x < \infty

Range : f (x) \geq - 28

X Intercepts : (2, 0), (- 2, 0), Y Intercepts : (0, - 28)

Asymptotes : None

Extreme Points : Minimum (0, - 28)

Interval Notation

Domain : (- \infty, \infty)

Range : [- 28, \infty)

Solution steps

Domain of

(x^{2} - x + 1) (x^{2} + x + 1) + 2 x^{2} - 29 : - \infty < x < \infty

Range of

(x^{2} - x + 1) (x^{2} + x + 1) + 2 x^{2} - 29 : f (x) \geq - 28

Axis interception points of

(x^{2} - x + 1) (x^{2} + x + 1) + 2 x^{2} - 29 :

X Intercepts

: (2, 0), (- 2, 0),

Y Intercepts

: (0, - 28)

Asymptotes of

(x^{2} - x + 1) (x^{2} + x + 1) + 2 x^{2} - 29 :

None

Extreme Points of

(x^{2} - x + 1) (x^{2} + x + 1) + 2 x^{2} - 29 :

Minimum

(0, - 28)

f (x) = x^{3} + 2 x^{2} + 2 x + 9

y = - (x - 3) 2 + 5

f (n) = 4.6 9^{n} + 1

f (n) = 3 n^{2} + 17 n + 1156

f (a) = a^{2} + 7 a + 78

What is the p(x)=(x^2-x+1)(x^2+x+1)+2x^2-29 ?
The p(x)=(x^2-x+1)(x^2+x+1)+2x^2-29 is