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Popular >

f(x)=|x^2-1|(x+1)

Solution

f (x) = x^{2} - 1 (x + 1)

Solution

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

X Intercepts : (- 1, 0), (1, 0), Y Intercepts : (0, 1)

Asymptotes : None

Extreme Points : Saddle (- 1, 0), Maximum (\frac{1}{3}, \frac{32}{27}), Minimum (1, 0)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

x^{2} - 1 (x + 1) : - \infty < x < \infty

Range of

x^{2} - 1 (x + 1) : - \infty < f (x) < \infty

Axis interception points of

x^{2} - 1 (x + 1) :

X Intercepts

: (- 1, 0), (1, 0),

Y Intercepts

: (0, 1)

Asymptotes of

x^{2} - 1 (x + 1) :

None

Extreme Points of

x^{2} - 1 (x + 1) :

Saddle

(- 1, 0),

Maximum

(\frac{1}{3}, \frac{32}{27}),

Minimum

(1, 0)

Graph

Popular Examples

f(x)= 4/((2x+6))

f (x) = \frac{4}{( 2 x + 6 )}

y=2x^3-15x^2+36x+20

y = 2 x^{3} - 15 x^{2} + 36 x + 20

y=((1+cos^2(x)))/((3-2sin^2(x)))

y = \frac{( 1 + cos ^{2} ( x ) )}{( 3 - 2 sin ^{2} ( x ) )}

f(x)=tan^2(sqrt(x))

f (x) = tan^{2} (x)

f(p_{3})=8p_{3}

f (p_{3}) = 8 p_{3}

Frequently Asked Questions (FAQ)

What is the f(x)=|x^2-1|(x+1) ?
The f(x)=|x^2-1|(x+1) is