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Popular >

h(t)=-0.0625t^2+3t-20

Solution

h (t) = - 0.0625 t^{2} + 3 t - 20

Solution

Domain : - \infty < t < \infty

Range : f (t) \leq 16

X Intercepts : (\frac{1}{0.125}, 0), (\frac{5}{0.125}, 0), Y Intercepts : (0, - 20)

Inverse : - \frac{- 3 + - 0.25 t + 4}{0.125}, - \frac{- 3 - - 0.25 t + 4}{0.125}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 16]

Solution steps

Domain of

- 0.0625 t^{2} + 3 t - 20 : - \infty < t < \infty

Range of

- 0.0625 t^{2} + 3 t - 20 : f (t) \leq 16

Axis interception points of

- 0.0625 t^{2} + 3 t - 20 :

X Intercepts

: (\frac{1}{0.125}, 0), (\frac{5}{0.125}, 0),

Y Intercepts

: (0, - 20)

Inverse of

- 0.0625 t^{2} + 3 t - 20 : - \frac{- 3 + - 0.25 t + 4}{0.125}, - \frac{- 3 - - 0.25 t + 4}{0.125}

Popular Examples

f(x)=17x^2+9x-4

f (x) = 17 x^{2} + 9 x - 4

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f (t) = sinh^{3} (2 t)

f(x)=-1/3*x^2+4/3*x-16/3

f (x) = - \frac{1}{3} \cdot x^{2} + \frac{4}{3} \cdot x - \frac{16}{3}

f(x)=((cos(6x)+1))/((2sin(x)))

f (x) = \frac{( cos ( 6 x ) + 1 )}{( 2 sin ( x ) )}

f(x)=64x^2-40x-23

f (x) = 64 x^{2} - 40 x - 23

Frequently Asked Questions (FAQ)

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