What is the critical f(x)=2sqrt(x)-8x ?

The critical f(x)=2sqrt(x)-8x is x=0,x= 1/64

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critical f(x)=2sqrt(x)-8x

critical points

f (x) = 2 x - 8 x

x = 0, x = \frac{1}{64}

Solution steps

2 x - 8 x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{64}, x = 0

Identify critical points not in

f (x)

domain

Domain of

2 x - 8 x : x \geq 0

All critical points are in domain

x = 0, x = \frac{1}{64}

(5.3) (2)

x^{3} - 3 x + 3

2 y - 7 = - 3 (2 - 2 x)

- 2

y = - x^{2} + 2 x + 3

What is the critical f(x)=2sqrt(x)-8x ?
The critical f(x)=2sqrt(x)-8x is x=0,x= 1/64