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Popular >

f(s)=((s-4))/((10s^2+2s-8))

Solution

f (s) = \frac{( s - 4 )}{( 10 s ^{2} + 2 s - 8 )}

Solution

Domain : s < - 1 or - 1 < s < \frac{4}{5} or s > \frac{4}{5}

Range : f (s) \leq \frac{1}{162} or f (s) \geq \frac{1}{2}

X Intercepts : (4, 0), Y Intercepts : (0, \frac{1}{2})

Asymptotes : Vertical s = - 1, s = \frac{4}{5}, Horizontal y = 0

Extreme Points : Minimum (0, \frac{1}{2}), Maximum (8, \frac{1}{162})

+1

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, \frac{4}{5}) \cup (\frac{4}{5}, \infty)

Range : (- \infty, \frac{1}{162}] \cup [\frac{1}{2}, \infty)

Solution steps

Domain of

\frac{s - 4}{10 s ^{2} + 2 s - 8} : s < - 1 or - 1 < s < \frac{4}{5} or s > \frac{4}{5}

Range of

\frac{s - 4}{10 s ^{2} + 2 s - 8} : f (s) \leq \frac{1}{162} or f (s) \geq \frac{1}{2}

Axis interception points of

\frac{s - 4}{10 s ^{2} + 2 s - 8} :

X Intercepts

: (4, 0),

Y Intercepts

: (0, \frac{1}{2})

Asymptotes of

\frac{s - 4}{10 s ^{2} + 2 s - 8} :

Vertical

: s = - 1, s = \frac{4}{5},

Horizontal

: y = 0

Extreme Points of

\frac{s - 4}{10 s ^{2} + 2 s - 8} :

Minimum

(0, \frac{1}{2}),

Maximum

(8, \frac{1}{162})

Popular Examples

f (4) = - 2 x + 8

f(x)=-7+8x^2-4x

f (x) = - 7 + 8 x^{2} - 4 x

f(t)=ln(cos^2(t))

f (t) = ln (cos^{2} (t))

f(x)=(x-1)-ln(x+1)

f (x) = (x - 1) - ln (x + 1)

f(x)=x^4-x^2+12

f (x) = x^{4} - x^{2} + 12

Frequently Asked Questions (FAQ)

What is the f(s)=((s-4))/((10s^2+2s-8)) ?
The f(s)=((s-4))/((10s^2+2s-8)) is