What is the perpendicular y+3x-5=0 ?

The perpendicular y+3x-5=0 is y= 1/3 x+b

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perpendicular y+3x-5=0

perpendicular

y + 3 x - 5 = 0

y = \frac{1}{3} x + b

Solution steps

Find the slope of

y + 3 x - 5 = 0 : m = - 3

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{3}

Line with slope m=

\frac{1}{3} : y = \frac{1}{3} x + b

y = \frac{1}{3} x + b

\frac{d}{x d x}

f (x) = 4 x^{4} - 8 x^{3} + 4

f (x) = 3 x (x + 5)^{2}

f (x) = 2 x^{2} + 8 x - 6

f (x) = sec (x)