What is the s(t)=((t^4)/3)2-4(t 1/3 (t^4)/(12)) ?

The s(t)=((t^4)/3)2-4(t 1/3 (t^4)/(12)) is

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s(t)=((t^4)/3)2-4(t 1/3 (t^4)/(12))

s (t) = (\frac{t ^{4}}{3}) 2 - 4 (t \frac{1}{3} \frac{t ^{4}}{12})

Domain : - \infty < t < \infty

Range : - \infty < f (t) < \infty

X Intercepts : (0, 0), (6, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Minimum (0, 0), Maximum (\frac{24}{5}, \frac{221184}{3125})

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{t ^{4}}{3} 2 - 4 t \frac{1}{3} \frac{t ^{4}}{12} : - \infty < t < \infty

Range of

\frac{t ^{4}}{3} 2 - 4 t \frac{1}{3} \frac{t ^{4}}{12} : - \infty < f (t) < \infty

Axis interception points of

\frac{t ^{4}}{3} 2 - 4 t \frac{1}{3} \frac{t ^{4}}{12} :

X Intercepts

: (0, 0), (6, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{t ^{4}}{3} 2 - 4 t \frac{1}{3} \frac{t ^{4}}{12} :

None

Extreme Points of

\frac{t ^{4}}{3} 2 - 4 t \frac{1}{3} \frac{t ^{4}}{12} :

Minimum

(0, 0),

Maximum

(\frac{24}{5}, \frac{221184}{3125})

f (x) = 13 x^{2} + 8 x - 4

f (x) = e^{x} + x + 1

f (y) = x^{2} - x + 1

y = x^{4} - 12 x^{3} + 48 x^{2} - 64 x

f (x) = cos (x^{2} + 9)

What is the s(t)=((t^4)/3)2-4(t 1/3 (t^4)/(12)) ?
The s(t)=((t^4)/3)2-4(t 1/3 (t^4)/(12)) is