What is the f(x)=arctan(((2x))/((1+x^2))) ?

The f(x)=arctan(((2x))/((1+x^2))) is

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f(x)=arctan(((2x))/((1+x^2)))

f (x) = arctan (\frac{( 2 x )}{( 1 + x ^{2} )})

Domain : - \infty < x < \infty

Range : - \frac{π}{4} \leq f (x) \leq \frac{π}{4}

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = 0

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{π}{4}, \frac{π}{4}]

Solution steps

Domain of

arctan (\frac{2 x}{1 + x ^{2}}) : - \infty < x < \infty

Range of

arctan (\frac{2 x}{1 + x ^{2}}) : - \frac{π}{4} \leq f (x) \leq \frac{π}{4}

Axis interception points of

arctan (\frac{2 x}{1 + x ^{2}}) :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

arctan (\frac{2 x}{1 + x ^{2}}) :

Horizontal

: y = 0

f (x) = arccos (x) + arccos (1 - x)

f (w) = w^{6} + w^{3} + 1

f (x) = \frac{( x ^{2} - 1 ) ^{- 1}}{2}

y = - 3 (x + 2)^{2} + 4

f (x) = 7 x^{3} - 2 x^{2} - 16 x - 32

What is the f(x)=arctan(((2x))/((1+x^2))) ?
The f(x)=arctan(((2x))/((1+x^2))) is