What is the shift f(x)=4sin(2x-pi) ?

The shift f(x)=4sin(2x-pi) is Phase: pi/2 , Vertical:0

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shift f(x)=4sin(2x-pi)

shift

f (x) = 4 sin (2 x - π)

Phase : \frac{π}{2}, Vertical : 0

Solution steps

f (x) = 4 sin (2 x - π)

g (B x - C) = sin (2 x - π), B = 2, C = π, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{π}{2}

\frac{π}{2}

The vertical shift

D

0

0

f (x) = 4 x^{2} - 5

f (x) = - 4^{x + 5}

y = - \frac{3}{4} x - \frac{3}{2}

f (x) = 2 (x - 3)^{2} + 4

4 x + 20 y = - 180

What is the shift f(x)=4sin(2x-pi) ?
The shift f(x)=4sin(2x-pi) is Phase: pi/2 , Vertical:0