en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

h(8)= 1/(((1-t)^2)+4(2t-1))

Solution

h (8) = \frac{1}{( ( 1 - t ) ^{2} ) + 4 ( 2 t - 1 )}

Solution

Domain : t < - 3 - 23 or - 3 - 23 < t < - 3 + 23 or t > - 3 + 23

Range : f (t) \leq - \frac{1}{12} or f (t) > 0

Y Intercepts : (0, - \frac{1}{3})

Asymptotes : Vertical t = - 3 - 23, t = - 3 + 23, Horizontal y = 0

Extreme Points : Maximum (- 3, - \frac{1}{12})

+1

Solution steps

Domain of

\frac{1}{( 1 - t ) ^{2} + 4 ( 2 t - 1 )} : t < - 3 - 23 or - 3 - 23 < t < - 3 + 23 or t > - 3 + 23

Range of

\frac{1}{( 1 - t ) ^{2} + 4 ( 2 t - 1 )} : f (t) \leq - \frac{1}{12} or f (t) > 0

Axis interception points of

\frac{1}{( 1 - t ) ^{2} + 4 ( 2 t - 1 )} :

Y Intercepts

: (0, - \frac{1}{3})

Asymptotes of

\frac{1}{( 1 - t ) ^{2} + 4 ( 2 t - 1 )} :

Vertical

: t = - 3 - 23, t = - 3 + 23,

Horizontal

: y = 0

Extreme Points of

\frac{1}{( 1 - t ) ^{2} + 4 ( 2 t - 1 )} :

Maximum

(- 3, - \frac{1}{12})

Popular Examples

f(t)=t^2+120t-360

f (t) = t^{2} + 120 t - 360

x = 4 t + 2

h(x)=((2x^4-3))/((4x))

h (x) = \frac{( 2 x ^{4} - 3 )}{( 4 x )}

f(x)=x^3-23x^2-34x-32

f (x) = x^{3} - 23 x^{2} - 34 x - 32

y=-x^3+9x^2-15x+2

y = - x^{3} + 9 x^{2} - 15 x + 2

Frequently Asked Questions (FAQ)

What is the h(8)= 1/(((1-t)^2)+4(2t-1)) ?
The h(8)= 1/(((1-t)^2)+4(2t-1)) is