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Popular >

y=((x^2+x-1))/((x+2))

Solution

y = \frac{( x ^{2} + x - 1 )}{( x + 2 )}

Solution

Domain : x < - 2 or x > - 2

Range : f (x) \leq - 5 or f (x) \geq - 1

X Intercepts : (\frac{- 1 + 5}{2}, 0), (\frac{- 1 - 5}{2}, 0), Y Intercepts : (0, - \frac{1}{2})

Asymptotes : Vertical x = - 2, Slant y = x - 1

Extreme Points : Maximum (- 3, - 5), Minimum (- 1, - 1)

+1

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, \infty)

Range : (- \infty, - 5] \cup [- 1, \infty)

Solution steps

Domain of

\frac{x ^{2} + x - 1}{x + 2} : x < - 2 or x > - 2

Range of

\frac{x ^{2} + x - 1}{x + 2} : f (x) \leq - 5 or f (x) \geq - 1

Axis interception points of

\frac{x ^{2} + x - 1}{x + 2} :

X Intercepts

: (\frac{- 1 + 5}{2}, 0), (\frac{- 1 - 5}{2}, 0),

Y Intercepts

: (0, - \frac{1}{2})

Asymptotes of

\frac{x ^{2} + x - 1}{x + 2} :

Vertical

: x = - 2,

Slant

: y = x - 1

Extreme Points of

\frac{x ^{2} + x - 1}{x + 2} :

Maximum

(- 3, - 5),

Minimum

(- 1, - 1)

Popular Examples

y=4+2x+3x^2+5x^3+8x^4

y = 4 + 2 x + 3 x^{2} + 5 x^{3} + 8 x^{4}

f(x)=5*(4x-1)^{-1}

f (x) = 5 \cdot (4 x - 1)^{- 1}

f(x)=(ln(x)+1)/x

f (x) = \frac{ln ( x ) + 1}{x}

g(x)=-7x^7-x^3+5x

g (x) = - 7 x^{7} - x^{3} + 5 x

f(m)=(8m^2-18)/(m^4)

f (m) = \frac{8 m ^{2} - 18}{m ^{4}}

Frequently Asked Questions (FAQ)

What is the y=((x^2+x-1))/((x+2)) ?
The y=((x^2+x-1))/((x+2)) is