What is the y=3cos^2(x)+2sin^2(x)-4cos(x)-2 ?

The y=3cos^2(x)+2sin^2(x)-4cos(x)-2 is

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y=3cos^2(x)+2sin^2(x)-4cos(x)-2

y = 3 cos^{2} (x) + 2 sin^{2} (x) - 4 cos (x) - 2

Period : 2 π

Domain : - \infty < x < \infty

Range : - 3 \leq f (x) \leq 5

X Intercepts : (\frac{π}{2} + 2 πn, 0), (\frac{3 π}{2} + 2 πn, 0), Y Intercepts : (0, - 3)

Asymptotes : None

Extreme Points : Minimum (2 πn, - 3), Maximum (π + 2 πn, 5)

Interval Notation

Domain : (- \infty, \infty)

Range : [- 3, 5]

Solution steps

Periodicity of

3 cos^{2} (x) + 2 sin^{2} (x) - 4 cos (x) - 2 : 2 π

Domain of

3 cos^{2} (x) + 2 sin^{2} (x) - 4 cos (x) - 2 : - \infty < x < \infty

Range of

3 cos^{2} (x) + 2 sin^{2} (x) - 4 cos (x) - 2 : - 3 \leq f (x) \leq 5

Axis interception points of

3 cos^{2} (x) + 2 sin^{2} (x) - 4 cos (x) - 2 :

X Intercepts

: (\frac{π}{2} + 2 πn, 0), (\frac{3 π}{2} + 2 πn, 0),

Y Intercepts

: (0, - 3)

Asymptotes of

3 cos^{2} (x) + 2 sin^{2} (x) - 4 cos (x) - 2 :

None

Extreme Points of

3 cos^{2} (x) + 2 sin^{2} (x) - 4 cos (x) - 2 :

Minimum

(2 πn, - 3),

Maximum

(π + 2 πn, 5)

y = (3 x^{2} + x - 5)

y = sin^{2} (x) + 7

f (s) = \frac{( s ^{2} + 3 s + 4 )}{( ( s + 1 ) ^{3} )}

f (x) = x^{3} - 10 x^{2} + 1

y = \frac{x ^{3}}{3} - 5 \frac{x ^{2}}{2} + 6 x + 1

What is the y=3cos^2(x)+2sin^2(x)-4cos(x)-2 ?
The y=3cos^2(x)+2sin^2(x)-4cos(x)-2 is