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Popular >

midpoint (-1,6),(5,-3)

Solution

midpoint

(- 1, 6), (5, - 3)

Solution

(2, \frac{3}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 1, 6), (x_{2}, y_{2}) = (5, - 3)

= (\frac{5 - 1}{2}, \frac{- 3 + 6}{2})

Refine

= (2, \frac{3}{2})

Popular Examples

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distance (-7,6),(3,0)distance

(- 7, 6), (3, 0)

range of x/9 range

\frac{x}{9}

critical x^2+2x-3 critical points

x^{2} + 2 x - 3

domain of f(x)=ln(pi/x)+arctan(2x)domain

f (x) = ln (\frac{π}{x}) + arctan (2 x)

Frequently Asked Questions (FAQ)

What is the midpoint (-1,6),(5,-3) ?
The midpoint (-1,6),(5,-3) is (2, 3/2)