What is the f(x)=((x^4-3x^3-6x^2-3x+2))/x ?

The f(x)=((x^4-3x^3-6x^2-3x+2))/x is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=((x^4-3x^3-6x^2-3x+2))/x

f (x) = \frac{( x ^{4} - 3 x ^{3} - 6 x ^{2} - 3 x + 2 )}{x}

Domain : x < 0 or x > 0

X Intercepts : (0.36231 \dots, 0), (4.47002 \dots, 0)

Asymptotes : Vertical x = 0

Extreme Points : Maximum (- 0.93833 \dots, - 2.96902 \dots), Minimum (2.75718 \dots, - 20.66362 \dots)

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{x ^{4} - 3 x ^{3} - 6 x ^{2} - 3 x + 2}{x} : x < 0 or x > 0

Axis interception points of

\frac{x ^{4} - 3 x ^{3} - 6 x ^{2} - 3 x + 2}{x} :

X Intercepts

: (0.36231 \dots, 0), (4.47002 \dots, 0)

Asymptotes of

\frac{x ^{4} - 3 x ^{3} - 6 x ^{2} - 3 x + 2}{x} :

Vertical

: x = 0

Extreme Points of

\frac{x ^{4} - 3 x ^{3} - 6 x ^{2} - 3 x + 2}{x} :

Maximum

(- 0.93833 \dots, - 2.96902 \dots),

Minimum

(2.75718 \dots, - 20.66362 \dots)

y = \frac{5 x}{3 + 3}

f (x) = 6 + 27 x - 1

f (n) = n^{2} + 241 n - 2400

y = \frac{2}{3} x + \frac{52}{3}

y = (7 x^{2} + 4 x) (3 x + 4)

What is the f(x)=((x^4-3x^3-6x^2-3x+2))/x ?
The f(x)=((x^4-3x^3-6x^2-3x+2))/x is