What is the f(x)=(4x-3)^{1/2}-x(4x-3)^{1/2}+x ?

The f(x)=(4x-3)^{1/2}-x(4x-3)^{1/2}+x is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=(4x-3)^{1/2}-x(4x-3)^{1/2}+x

f (x) = (4 x - 3)^{\frac{1}{2}} - x (4 x - 3)^{\frac{1}{2}} + x

Domain : x \geq \frac{3}{4}

X Intercepts : (1.88464 \dots, 0)

Asymptotes : None

Extreme Points : Minimum (\frac{3}{4}, \frac{3}{4}), Maximum (1, 1)

Interval Notation

Domain : [\frac{3}{4}, \infty)

Solution steps

Domain of

(4 x - 3)^{\frac{1}{2}} - x (4 x - 3)^{\frac{1}{2}} + x : x \geq \frac{3}{4}

Axis interception points of

(4 x - 3)^{\frac{1}{2}} - x (4 x - 3)^{\frac{1}{2}} + x :

X Intercepts

: (1.88464 \dots, 0)

Asymptotes of

(4 x - 3)^{\frac{1}{2}} - x (4 x - 3)^{\frac{1}{2}} + x :

None

Extreme Points of

(4 x - 3)^{\frac{1}{2}} - x (4 x - 3)^{\frac{1}{2}} + x :

Minimum

(\frac{3}{4}, \frac{3}{4}),

Maximum

(1, 1)

y = cos (2 x) + 8 cos (n) + 1

f (x) = \frac{1}{2} \frac{csc ( x )}{4}

y = x^{3} + 3 x^{2} - 9 x

y = (3 p - 36) \cdot x^{2} + 5 x

f (x) = (1 - x^{2}) \cdot e^{\frac{- ( x ^{2} )}{2}}

What is the f(x)=(4x-3)^{1/2}-x(4x-3)^{1/2}+x ?
The f(x)=(4x-3)^{1/2}-x(4x-3)^{1/2}+x is