What is the f(y)=sqrt(3)*y^2+9y+6sqrt(3) ?

The f(y)=sqrt(3)*y^2+9y+6sqrt(3) is

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f(y)=sqrt(3)*y^2+9y+6sqrt(3)

f (y) = 3 \cdot y^{2} + 9 y + 63

Domain : - \infty < y < \infty

Range : f (y) \geq 63 - \frac{27 3}{4}

X Intercepts : (- 3, 0), (- 23, 0), Y Intercepts : (0, 63)

Inverse : \frac{3 ( - 9 + 4 3 y + 9 )}{6}, \frac{3 ( - 9 - 4 3 y + 9 )}{6}

Interval Notation

Domain : (- \infty, \infty)

Range : [63 - \frac{27 3}{4}, \infty)

Solution steps

Domain of

3 \cdot y^{2} + 9 y + 63 : - \infty < y < \infty

Range of

3 \cdot y^{2} + 9 y + 63 : f (y) \geq 63 - \frac{27 3}{4}

Axis interception points of

3 \cdot y^{2} + 9 y + 63 :

X Intercepts

: (- 3, 0), (- 23, 0),

Y Intercepts

: (0, 63)

Inverse of

3 \cdot y^{2} + 9 y + 63 : \frac{3 ( - 9 + 4 3 y + 9 )}{6}, \frac{3 ( - 9 - 4 3 y + 9 )}{6}

f (x) = 3 sin (x) + x^{3}

f (x) = x^{3} + 3 x^{2} - 4 x + 2

f (x) = - 3 x^{2} + 5 x + 3

f (x) = 2 x^{3} + 2 x + 3

g (t) = - 9 t - 4