What is the range of f(x)=2sqrt(x+5) ?

The range of f(x)=2sqrt(x+5) is f(x)>= 0

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range of f(x)=2sqrt(x+5)

range

f (x) = 2 x + 5

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = \frac{x - 4}{3 x + 5}

f (x) = \frac{x}{( x - 1 ) ^{2}}

x^{3} + 2 x^{2} - 9 x - 18

f (x) = x + 4 - \frac{8 - x}{x}

f (x) = \frac{- x ^{2} + 6 x + 1}{x - 2}