What is the g(x)=(((x+1)(x+2)))/(((x-1)(x-2))) ?

The g(x)=(((x+1)(x+2)))/(((x-1)(x-2))) is

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g(x)=(((x+1)(x+2)))/(((x-1)(x-2)))

g (x) = \frac{( ( x + 1 ) ( x + 2 ) )}{( ( x - 1 ) ( x - 2 ) )}

Domain : x < 1 or 1 < x < 2 or x > 2

Range : f (x) \leq - 122 - 17 or f (x) \geq 122 - 17

X Intercepts : (- 1, 0), (- 2, 0), Y Intercepts : (0, 1)

Asymptotes : Vertical x = 1, x = 2, Horizontal y = 1

Extreme Points : Minimum (- 2, - 17 + 122), Maximum (2, - 17 - 122)

Interval Notation

Domain : (- \infty, 1) \cup (1, 2) \cup (2, \infty)

Range : (- \infty, - 122 - 17] \cup [122 - 17, \infty)

Solution steps

Domain of

\frac{( x + 1 ) ( x + 2 )}{( x - 1 ) ( x - 2 )} : x < 1 or 1 < x < 2 or x > 2

Range of

\frac{( x + 1 ) ( x + 2 )}{( x - 1 ) ( x - 2 )} : f (x) \leq - 122 - 17 or f (x) \geq 122 - 17

Axis interception points of

\frac{( x + 1 ) ( x + 2 )}{( x - 1 ) ( x - 2 )} :

X Intercepts

: (- 1, 0), (- 2, 0),

Y Intercepts

: (0, 1)

Asymptotes of

\frac{( x + 1 ) ( x + 2 )}{( x - 1 ) ( x - 2 )} :

Vertical

: x = 1, x = 2,

Horizontal

: y = 1

Extreme Points of

\frac{( x + 1 ) ( x + 2 )}{( x - 1 ) ( x - 2 )} :

Minimum

(- 2, - 17 + 122),

Maximum

(2, - 17 - 122)

y = \frac{( x ^{3} )}{( 4 - 7 x ^{2} )}

f (x) = \frac{x ^{7} + 1}{x ^{7}}

f = (16 n^{0.12} n)

y = ln (\frac{5 x - 1}{x + 4})

f (x) = \frac{2}{9 x ( 3 - x )}

What is the g(x)=(((x+1)(x+2)))/(((x-1)(x-2))) ?
The g(x)=(((x+1)(x+2)))/(((x-1)(x-2))) is