What is the f(x)=sqrt(2x-1)+2sqrt(x^2-x-6) ?

The f(x)=sqrt(2x-1)+2sqrt(x^2-x-6) is

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f(x)=sqrt(2x-1)+2sqrt(x^2-x-6)

f (x) = 2 x - 1 + 2 x^{2} - x - 6

Domain : x \geq 3

Range : f (x) \geq 5

Intercepts : None

Asymptotes : None

Extreme Points : Minimum (3, 5)

Interval Notation

Domain : [3, \infty)

Range : [5, \infty)

Solution steps

Domain of

2 x - 1 + 2 x^{2} - x - 6 : x \geq 3

Range of

2 x - 1 + 2 x^{2} - x - 6 : f (x) \geq 5

Axis interception points of

2 x - 1 + 2 x^{2} - x - 6 :

None

Asymptotes of

2 x - 1 + 2 x^{2} - x - 6 :

None

Extreme Points of

2 x - 1 + 2 x^{2} - x - 6 :

Minimum

(3, 5)

y = 2 x^{3} - 3 x^{2} - 2 x + 3

f (x) = 5147 x^{53}

y = 2 x^{3} - 15 x^{2} + 24 x

y = 2 tan (x) + 3

m (v) = \frac{10}{( 2 - \frac{1}{v} )}

What is the f(x)=sqrt(2x-1)+2sqrt(x^2-x-6) ?
The f(x)=sqrt(2x-1)+2sqrt(x^2-x-6) is