What is the s(t)=((t^3))/5-2/((t^2))+6/t-3/5 ?

The s(t)=((t^3))/5-2/((t^2))+6/t-3/5 is

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s(t)=((t^3))/5-2/((t^2))+6/t-3/5

s (t) = \frac{( t ^{3} )}{5} - \frac{2}{( t ^{2} )} + \frac{6}{t} - \frac{3}{5}

Domain : t < 0 or t > 0

X Intercepts : (0.34507 \dots, 0)

Asymptotes : None

Extreme Points : Maximum (- 1.91609 \dots, - 5.68307 \dots), Maximum (0.68135 \dots, 3.96117 \dots), Minimum (1.54392 \dots, 3.18322 \dots)

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{t ^{3}}{5} - \frac{2}{t ^{2}} + \frac{6}{t} - \frac{3}{5} : t < 0 or t > 0

Axis interception points of

\frac{t ^{3}}{5} - \frac{2}{t ^{2}} + \frac{6}{t} - \frac{3}{5} :

X Intercepts

: (0.34507 \dots, 0)

Asymptotes of

\frac{t ^{3}}{5} - \frac{2}{t ^{2}} + \frac{6}{t} - \frac{3}{5} :

None

Extreme Points of

\frac{t ^{3}}{5} - \frac{2}{t ^{2}} + \frac{6}{t} - \frac{3}{5} :

Maximum

(- 1.91609 \dots, - 5.68307 \dots),

Maximum

(0.68135 \dots, 3.96117 \dots),

Minimum

(1.54392 \dots, 3.18322 \dots)

y = \frac{2}{3 ( 3 ) ^{x}}

f (x) = cos^{60} (+ x)

f (x) = \frac{( x ^{2} - 4 ) 4}{3}

f (5) = x + 3 x

y = lo g_{5} (x) + lo g_{x} (5) + lo g_{5} (5)

What is the s(t)=((t^3))/5-2/((t^2))+6/t-3/5 ?
The s(t)=((t^3))/5-2/((t^2))+6/t-3/5 is