What is the f(x)=((x^4-13x^2+36))/((x^2-1)) ?

The f(x)=((x^4-13x^2+36))/((x^2-1)) is

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f(x)=((x^4-13x^2+36))/((x^2-1))

f (x) = \frac{( x ^{4} - 13 x ^{2} + 36 )}{( x ^{2} - 1 )}

Domain : x < - 1 or - 1 < x < 1 or x > 1

Range : f (x) \leq - 36 or f (x) \geq 46 - 11

X Intercepts : (3, 0), (- 3, 0), (2, 0), (- 2, 0), Y Intercepts : (0, - 36)

Asymptotes : Vertical x = - 1, x = 1

Extreme Points : Minimum (- 1 + 26, \frac{24 - 11 6}{6}), Maximum (0, - 36), Minimum (1 + 26, \frac{24 - 11 6}{6})

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Range : (- \infty, - 36] \cup [46 - 11, \infty)

Solution steps

Domain of

\frac{x ^{4} - 13 x ^{2} + 36}{x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

Range of

\frac{x ^{4} - 13 x ^{2} + 36}{x ^{2} - 1} : f (x) \leq - 36 or f (x) \geq 46 - 11

Axis interception points of

\frac{x ^{4} - 13 x ^{2} + 36}{x ^{2} - 1} :

X Intercepts

: (3, 0), (- 3, 0), (2, 0), (- 2, 0),

Y Intercepts

: (0, - 36)

Asymptotes of

\frac{x ^{4} - 13 x ^{2} + 36}{x ^{2} - 1} :

Vertical

: x = - 1, x = 1

Extreme Points of

\frac{x ^{4} - 13 x ^{2} + 36}{x ^{2} - 1} :

Minimum

(- 1 + 26, \frac{24 - 11 6}{6}),

Maximum

(0, - 36),

Minimum

(1 + 26, \frac{24 - 11 6}{6})

f (x) = 3 - 7 x + 5 x^{2}

f (x) = (2 x + x^{2}) 4

g (s) = \frac{1}{( s ^{3} + 7 s ^{2} + 12 s )}

h (x) = 10 - 5 x

f (2) = x^{2} - 3 (2) - 3

What is the f(x)=((x^4-13x^2+36))/((x^2-1)) ?
The f(x)=((x^4-13x^2+36))/((x^2-1)) is