What is the periodicity of y=sin^2(x)cot^2(2x) ?

The periodicity of y=sin^2(x)cot^2(2x) is pi

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periodicity of y=sin^2(x)cot^2(2x)

periodicity

y = sin^{2} (x) cot^{2} (2 x)

π

Solution steps

sin^{2} (x) cot^{2} (2 x)

is composed of the following functions and periods:

sin (x)

with periodicity of

2 π

The compound periodicity is:

= π

p (x) = x^{4} - 16

f (x) = (2 x^{2} - 3 x) (- 4 x^{2} + 5)

f (m) = 8 m^{2} + 9 m + 5

f (k) = 19 k^{2} + 23 k + 10

f (x) = \frac{( \frac{1}{2} ) ^{2} - 1}{2 - 2}

What is the periodicity of y=sin^2(x)cot^2(2x) ?
The periodicity of y=sin^2(x)cot^2(2x) is pi